Rate of effusion of LPG (a mixture of `n`-butane and propane) is 1.25 times that of `SO_(3)`. Hence, mole fraction of `n`-butane in LPG is

Rate of diffusion of LPG (a mixture of n-butane and propane) is 1.25 times that of SO_(3) Hence, mole fraction of n-butane in LPG is

At 298K , the vapour pressure of pure liquid n-butane is 1823 torr and vapour pressure of pure n-pentane is 521 torr and form nearly an ideal solution. a. Find the total vapour pressure at 298 K of a liquid solution containing 10% n-butane and 90% n-pentane by weight, b. Find the mole fraction of n-butane in solution exerting a total vapour pressure of 760 torr. c. What is composition of vapours of two components (mole fraction in vapour state)?

At 298K , the vapour pressure of pure liquid n-butane is 1823 torr and vapour pressure of pure n-pentane is 521 torr and form nearly an ideal solution. a. Find the total vapour pressure at 298 K of a liquid solution containing 10% n-butane and 90% n-pentane by weight, b. Find the mole fraction of n-butane in solution exerting a total vapour pressure of 760 torr. c. What is composition of vapours of two components (mole fraction in vapour state)?

At 298K , the vapour pressure of pure liquid n-butane is 1823 torr and vapour pressure of pure n-pentane is 521 torr and form nearly an ideal solution. a. Find the total vapour pressure at 298 K of a liquid solution containing 10% n-butane and 90% n-pentane by weight, b. Find the mole fraction of n-butane in solution exerting a total vapour pressure of 760 torr. c. What is composition of vapours of two components (mole fraction in vapour state)?

At what temperature, the rate of effusion of N_(2) would be 1.625 times that of SO_(2) at 50^(@)C ?

A what temperature, the rate of effusion of N_(2) would be 1.625 times that of SO_(2) at 50^(@)C ?

At what temperature, the rate of effusion of N_(2) would be 1.625 times that of SO_(2) at 50^(@)C ?