A body of mass M rests on a horizontal plane having coefficient of friction `mu` . At `t=0` a horizontal force `vec(F)` is applied that varies with time `vec(F)(t)=vec(F)_(0)` t where `vec(F)_(0)` is a constant vector. The time instant `t_(0)` at which motion starts and distance moved in t second will be:

A body of mass M is resting on a rough horizontal plane surface the coefficient of friction being equal to mu At t = 0 a horizontal force F = F_(0) t starts acting on it , where F_(0) is a constant find the time T at which the motion starts?

A body of mass M is resting on a rough horizontal plane surface the coefficient of friction being equal to mu At t = 0 a horizontal force F = F_(0) t starts acting on it , where F_(0) is a constant find the time T at which the motion starts?

A body of mass M is resting on a rough horizontal plane surface the coefficient of friction being equal to mu At t = 0 a horizontal force F = F_(0) t starts acting on it , where F_(0) is a constant find the time T at which the motion starts?

A bar of mass m_(1) is placed on a plank of mass m_(2) which rests on a smooth horizontal plane . The coefficient of friction between the surfaces of bar and plank is k . The plank is subjected to a horizontal force F depending on time t as F = at , where a is a constant . The moment of time t_(0) at which the plank starts sliding is :

The velocity of a particle varies with time as per the law vec(V) = vec(a) + vec(b)t where vec(a) and vec(b) are two constant vectors. The time at which velocity of the particle is perpendicular to velocity of the particle at t= 0 is

At the moment t = 0 , the force F = kt is applied to a small body of mass 'm' resting on a smoth horizontal plane. (K is a positive constant ). The direction of the force an angle theta with the horizontal always as shown Consider the body to leave the surface at an instant t=t_0 then which of the following curves represent velocity ''V'' Vs time 't' for the motion of the body in the interval 0 lt t lt t_0