[" 10."x+2y+2=0],[quad 3x+2y-2=0]

x + 2y + 2 = 0 , 3x + 2y - 2 = 0

3x + 4y - 10 = 0 2x - 2y-2=0

The area of the parallelogram formed by the lines 2x-3y+a=0, 3x-2y-a=0, 2x-3y+3a=0 and 3x-2y-2a=0 in square units , is

Solve for x and y: 2x - 3y-13 =0 , 3x -2y+12 =0

If the area of the parallelogram formed by the lines 2x - 3y + a = 0 , 3x - 2y - a = 0 , 2x - 3y + 3a = 0 and 3x - 2y - 2a = 0 is 10 square units , then a =

If the area of the parallelogram formed by the lines 2x - 3y + a = 0 , 3x - 2y - a = 0 , 2x - 3y + 3a = 0 and 3x - 2y - 2a = 0 is 10 square units , then a =

If the area of the parallelogram formed by the lines 2x - 3y + a = 0 , 3x - 2y - a = 0 , 2x - 3y + 3a = 0 and 3x - 2y - 2a = 0 is 10 square units , then a =

The two curves x^3 - 3x y^2 + 2 = 0 and 3x^2y - y^3 - 2 = 0 intersect at an angle of

find x and y : 2x+y-5=0 3x+2y-8=0