cos theta+sin theta=cos2 theta+sin2 theta

Solve the equation 3-2cos theta-4sin theta-cos2 theta+sin2 theta=0

Find the value of theta, which satisfy 3-2cos theta-4sin theta-cos2 theta+sin2 theta=0

Find the most general value of theta, which satisfies 3-2cos theta-4sin theta-cos2 theta+sin2 theta=0

The value of (2(sin2 theta+2cos^(2)theta-1))/(cos theta-sin theta-cos3 theta+sin3 theta)=

Evaluate: int cos2 theta ln((cos theta+sin theta)/(cos theta-sin theta))d theta

If cos2 theta=0 If det[[0,cos theta,sin thetacos theta,sin theta,0sin theta,o,cos theta]]^(2)

If(cos theta+i sin theta)(cos2 theta+i sin2 theta).....(cos n theta+i sin n theta)=1 then the value of theta is:

Find the general value of theta which satisfies the equation (cos theta+i sin theta)(cos2 theta+i sin2 theta)......(cos n theta+i sin n theta)=1

Consider Delta ACB, right-angled at C, in which AB=29 units,BC=21 units and /_ABC=theta .Determine the values of (i)cos2 theta+sin2 theta(ii)cos2 theta sin2 theta

(sin theta-cos theta)/(sin theta+cos theta)+(sin theta+cos theta)/(sin theta-cos theta)=(2)/((2sin^(2)theta-1))