(x-19)/(z+1)=0," where "x,y,m,n" are real and "x+1y!=

If 1/ (m+i n) - (x-iy)/(x+iy) =0, where x,y,m,n are real and x+iy!=0 and m+i n!=0 , prove that m^2+n^2=1 .

If 1/ (m+i n) - (x-iy)/(x+iy) =0, where x,y,m,n are real and x+iy!=0 and m+i n!=0 , prove that m^2+n^2=1 .

If 36/11 = 3 + 1/(x + 1/(y + 1/z)) , where x, y and z are natural numbers, then what is (x+y+z) equal to ?

If (61)/(19) =3+(1)/(x+(1)/(y+(1)/(z))) where x, y and z are natural numbers, then what is z equal to?

If z=x+iy , where x and y are real numbers and |x|+|y| lt= k|z| then k=.....

Find the acute angle between the lines (x-1)/(l)=(y+1)/(m)=(1)/(n) and =(x+1)/(m)=(y-3)/(n)=(z-1)/(l) where l>m>n, and l,m,n are the roots of the cubic equation x^(3)+x^(2)-4x=4

Given a=x/(y-z),b=y/(z-x), and c=z/(x-y), where x,y,z and are not all zero,then the value of ab+bc+ca is 0 b.1 c.-1 none of these

The number of solutions to x+y+z=10 , where 1le x, y, z le 6 and x, y, z in N , is equal to