`[(3/9)^9 xx(3/4)^7] -: [(3/4)^6]^2`

(5/9xx-4/7-:8/-27)xx(3/-4)

(5)/(6) -: (6)/(7) xx ? - (8)/(9) -: 1 (2)/(5) -: (3)/(4) xx 3 (1)/(3) = 2(7)/(9)

Simplify : a. [(3^(3))xx3^(4)]-:3^(4) b. 18^(6)-:3^(12) c. [(5^(6))^(9)xx(5^(15))^(5)]-[(5^(13))^(5)xx(5^(4))^(16)] d. (3^(5)xx10^(5)xx25)-:(5^(7)xx6^(5)) e. ((2)/(b))^(18)xxb^(12)xx(3^(4))^(3) f. [(2^(4))^(2)xx2^(12)]-:4^(2) g. 12^(8)-:3^(6) h. [(7^(7))^(8)xx(7^(9))^(5)]-[(7^(11))^(6)xx(7^(7))^(5)] i. (25^(2)xxp^(4)xxq^(8))-:(5^(3)xxp^(4)xxq^(7)) j. ((a)/(3))^(24)xx2^(8)xx(3^(6))^(4)

Simplify: (a) 108-:36 of (1)/(4)+(2)/(5)xx3(1)/(4) (b) (2)/(3)xx(5)/(6)+(4)/(9)-(3)/(4)+(2)/(9)xx(5)/(9)-:(2)/(9)

Simplify : [ ((- 3 )/( 2) xx (4)/(5) ) + ((9)/(5) xx (-10)/( 3)) - ((1)/(2)xx (3)/(4)) ] div [ ((21)/( 9) xx (3)/(7)) +((7)/(8) xx (16)/(14)) ]

Find the value of x so that ((3)/(4))^(-9)times((3)/(4))^(-7)=((3)/(4))^(4x)

The value of (2)/(5) div (3)/(10) of (4)/(9) - (4)/(5) xx 1 (1)/(9) div (8)/(15) - (3)/(4) + (3)/(4) div (1)/(2) is: (a)7/9 (b)23/6 (c)4/3 (d)25/12

{:("Quantity A","Quantity B"),(3^(3)xx9^(6)xx2^(4)xx4^(2),9^(3)xx3^(6)xx2^(2)xx4^(4)):}