If `theta=60^@` then `1/2 sqrt(1+sin theta)+1/2sqrt(1-sin theta)=`

If theta = 60^@ , then 1/2 sqrt1 + sin theta + 1/2 sqrt1 -sin theta is equal to____

cos theta=sqrt(1-sin theta)

cos theta=sqrt(1-sin theta)

sqrt((1+sin theta)/(1-sin theta)?)?

cos theta sqrt(1-sin^(2)theta)=

If 0<=theta<=pi and (sin0)/(2)=sqrt(1+sin theta)-sqrt(1-sin theta) then the possible value of tan theta, is -

cos theta - sqrt3 sin theta = 1

If pi/2 < theta < pi, then sqrt((1- sin theta)/(1+ sin theta))+sqrt((1+ sin theta)/(1- sin theta)) is equal to

Evaluate: sqrt((1-sin theta)/(1+sin theta)) .

If pi/2 lt theta lt pi then sqrt((1-sin theta)/(1+sin theta))+sqrt((1+sin theta)/(1-sin theta))=