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Determine the potential at a point 0.50 ...

Determine the potential at a point 0.50 m (i) from a`+20 muC` potential charge (ii) from a`-20 muC` point charge.

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The potential due to a point charge is given by `V = (kQ)/(r )`
(a) At a distance of 0.50 m from a positive `20muC` charge, the potential is `V = (kQ)/(r )= (9.0 xx 10^(9) N.m^(2)//C^(2)) ((20 xx 10^(-6)C)/(0.50m))`
`=3.6 xx 10^(5)V`
(b) For the negative charge,
`V = (9.0 xx 10^(9) N m^(2)//C^(2)) ((-20 xx 10^(-6)C)/(0.50m))`
`=3.6 xx 10^(5)V`
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