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A bullet of mass 2 gm is having a charge...

A bullet of mass `2 gm` is having a charge of `2 muc`. Through what potential difference must it be accelerated, starting from rest, to acquire a speed of `10 m//s`

Text Solution

Verified by Experts

Use the reation `qV = (1)/(2) mv^(2)`, Here `m=2 xx 10^(-3) kg, v= 10 m//s`
Therefore `V = (mv^(2))/(2q) = (2 xx 10^(-3) xx (10)^(2))/(2 xx 2 xx 10^(-6)) = (10^(-1))/(2 xx 10^(-6))`
`=5 xx 10^(4) " volt" = 50kV`
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