An oil drop 'B' has charge `1.6 xx 10^(-19)C and " mass " 1.6 xx 10^(-14)kg`. If the drop is in equilibrium position, then what will be potential difference between the plates. [The distance between the plates is 100mm]

Explanation

To solve the problem of finding the potential difference between the plates given an oil drop in equilibrium, we can follow these steps:

### Step-by-Step Solution

1. **Identify the Forces Acting on the Oil Drop**:
The oil drop has a charge \( Q = 1.6 \times 10^{-19} \, \text{C} \) and a mass \( m = 1.6 \times 10^{-14} \, \text{kg} \). When the drop is in equilibrium, the electric force acting on it due to the electric field between the plates balances the gravitational force acting on it.

2. **Calculate the Gravitational Force**:
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