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Electric field intensity at a point B d...

Electric field intensity at a point B due to a point charge Q kept at point A is `24 NC^(-1)`, and electric potential at B due to the same charge is `12 JC^(-1)`. Calculate the distance `AB` and magnitude of charge.

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Here `E = 24N//C` , V = 12J/C
As `E = (V)/(r) , " " R= (V)/(E) = (12)/(24) (J//C)/(N//C) = 0.5 m`
As `V = k_(e) (Q)/(r)`
`Q = (Vr)/(K) = ((12J//C)(0.5m))/(9xx 10^(9) Nm^(2)//C^(2)) = 0.67 xx 10^(-9)C`
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