Two capacitors of capacitance 20.0 pF and 50.0 pF are connected is series with a battery of 20 V. Find the energy supplied by the battery.

Explanation

To find the energy supplied by the battery when two capacitors are connected in series, we can follow these steps:

### Step 1: Identify the capacitances
The given capacitances are:
- \( C_1 = 20.0 \, \text{pF} = 20 \times 10^{-12} \, \text{F} \)
- \( C_2 = 50.0 \, \text{pF} = 50 \times 10^{-12} \, \text{F} \)

### Step 2: Calculate the equivalent capacitance for capacitors in series
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