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At a point on the axis of an electric di...

At a point on the axis of an electric dipole

A

the electric field E is zero

B

the electric potential V is zero

C

both E and V are zero

D

neither E nor V is zero

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The correct Answer is:
To solve the problem regarding the electric field and electric potential at a point on the axis of an electric dipole, we can follow these steps: ### Step 1: Understanding the Electric Dipole An electric dipole consists of two equal and opposite charges, +Q and -Q, separated by a distance of 2L. The dipole moment \( p \) is defined as: \[ p = Q \cdot 2L \] ### Step 2: Determine the Position Let’s consider a point P located at a distance R from the center of the dipole along its axis. The distance from the positive charge (+Q) to point P is \( R - L \), and the distance from the negative charge (-Q) to point P is \( R + L \). ### Step 3: Calculate the Electric Potential (V) The electric potential \( V \) at point P due to the dipole is given by the formula: \[ V = k \left( \frac{Q}{R - L} - \frac{Q}{R + L} \right) \] where \( k \) is the Coulomb's constant. To simplify this, we can find a common denominator: \[ V = kQ \left( \frac{(R + L) - (R - L)}{(R - L)(R + L)} \right) \] This simplifies to: \[ V = kQ \left( \frac{2L}{R^2 - L^2} \right) \] ### Step 4: Analyze the Limit as R becomes much larger than L If \( R \) is much larger than \( L \) (i.e., \( R \gg L \)), we can neglect \( L^2 \) in the denominator: \[ V \approx \frac{2kQ \cdot L}{R^2} = \frac{kp}{R^2} \] This indicates that the electric potential is not zero at point P. ### Step 5: Calculate the Electric Field (E) The electric field \( E \) at point P due to the dipole can be calculated using: \[ E = -\frac{dV}{dR} \] Calculating the derivative of \( V \): \[ E = -\frac{d}{dR} \left( \frac{kp}{R^2} \right) = \frac{2kp}{R^3} \] This shows that the electric field is also not zero at point P. ### Step 6: Conclusion From the calculations: - The electric potential \( V \) at point P is not zero. - The electric field \( E \) at point P is also not zero. Thus, the correct answer is that neither the electric field nor the electric potential is zero at a point on the axis of an electric dipole.
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NARAYNA-ELECTROSTATIC POTENTIAL AND CAPACITANCE-C.U.Q (Potential and Potential Difference)
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  2. Charges are placed on the vertices of a square as shown Let vecE ...

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  3. The electric field and the potential of an electric dipole vary with d...

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  4. Which of the following is not true?

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  5. The value of electric potential at any point due to any electric dipol...

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  6. In case of a dipole field

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  7. At a point on the axis of an electric dipole

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  8. On the perpendicular bisector of an electric dipole, electric intensit...

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  9. The electric potential at a point on the axis of an electric dipole de...

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  10. Consider the following statements about electric dipole and select the...

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  11. A and B are two points on the axis and the perpendicular bisector of a...

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  12. Consider a uniform electric field in the hat (z) direction. The potent...

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  13. The work done to move a charge along an equipotential from A to B

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  14. What is angle between electric field and equipotential surface?

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  15. Equipotential surfaces

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  16. The top of the atomosphere is about 400 kV with respect to the surface...

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  17. An infinite cylinder of radius r(o), carrying linear charge density la...

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  18. An equipotential line and a line of force are

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  19. The equipotential surface corresponding to single positive charge are ...

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  20. Equipotential surfaces associated with an electric field which is incr...

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