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Electric field intensity at a point B d...

Electric field intensity at a point B due to a point charge Q kept at point A is `24 NC^(-1)`, and electric potential at B due to the same charge is `12 JC^(-1)`. Calculate the distance `AB` and magnitude of charge.

A

`10^(-6)C`

B

`10^(-7)C`

C

`10^(-10)C`

D

`10^(-9)C`

Text Solution

Verified by Experts

The correct Answer is:
D
`E = (1)/(4pi in_(0)) (q)/(r^(2)) V = (1)/(4pi in_(0)) (q)/(r )`
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