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A conducting sphere of radius R is charg...

A conducting sphere of radius R is charged to a potential of V volts. Then the electric field at a distance `r ( gt R)` from the centre of the sphere would be

A

`(RV)/(r^(2))`

B

`(V)/(R )`

C

`(rV)/(R^(2))`

D

`(R^(2)V)/(r^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
`V = (1)/(4pi in_(0)) (q)/(r )E = (1)/(4pi in_(0)) (q)/(r^(2))`
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NARAYNA-ELECTROSTATIC POTENTIAL AND CAPACITANCE-Exercise -1 (C.W)
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