A pellet carrying a charge of 0.5 coulomb is accelerated through a P.D of 2000 volt. It attains a kinetic energy equal to

Options

A. 1000 erg
B. 1000 joule
C. 1000 kwh
D. 500 erg

Explanation

To solve the problem of determining the kinetic energy attained by a pellet carrying a charge of 0.5 coulombs when accelerated through a potential difference of 2000 volts, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between work done and kinetic energy**:
According to the work-energy theorem, the work done on a charged particle in an electric field is equal to the change in its kinetic energy.

2. **Use the formula for work done in an electric field**:
The work done (W) on a charge (Q) when it is moved through a potential difference (V) is given by the formula:
\[ W = Q \times V \]

3. **Substitute the given values**:
Here, the charge \( Q = 0.5 \, \text{C} \) and the potential difference \( V = 2000 \, \text{V} \). Plugging these values into the formula gives:
\[ W = 0.5 \, \text{C} \times 2000 \, \text{V} \]

4. **Calculate the work done**:
\[ W = 0.5 \times 2000 = 1000 \, \text{J} \]

5. **Conclude the kinetic energy**:
Since the work done on the charge is converted into kinetic energy, we can conclude that the kinetic energy attained by the pellet is:
\[ KE = 1000 \, \text{J} \]

### Final Answer:
The kinetic energy attained by the pellet is **1000 Joules**.

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