Two charge each `Q` are released when the distance between is `d` .Then the velocity of each charge of mass `m` each when the distance between them is `2d` is

Options

A. `(Q)/(sqrt(8pi epsi_(0)dm))`
B. `(Q)/(sqrt(4pi epsi_(0)dm))`
C. `(Q)/(4sqrt(pi epsi_(0)dm))`
D. `(Q)/(sqrt(2pi epsi_(0)dm))`

Answer

A

Explanation

gain in K.E = loss in P.E 18 `(V_(1))/(V_(2)) = ((R_(1))/(R_(2)))^(3).(Q_(2))/(Q_(1))`