The force between the plates of a parallel plate capacitor of capacitance `C` and distance of separation of the plates `d` with a potential difference `V` between the plates, is.

Options

A. `(CV^(2))/(2d)`
B. `(C^(2)V^(2))/(2d^(2))`
C. `(C^(2)V^(2))/(d^(2))`
D. `(V^(2)d)/(C )`

Answer

A

Explanation

`F = (QE)/(2) = (CV)/(2) [(V)/(d)]`