Two identical capacitors 1 and 2 are connected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of dielectric constant K as shown. `Q_(1) and Q_(2)` are the charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are `Q_(1) and Q_(2)`. Then

Options

A. `(Q_(1))/(Q_(2)) = (K+1)/(K)`
B. `(Q_(2))/(Q_(2)) = (K+1)/(2)`
C. `(Q_(2))/(Q_(2)) = (K+1)/(2K)`
D. `(Q_(2))/(Q_(2)) = (K)/(2)`

Answer

C

Explanation

`Q_(1) = Q_(2) = (CE)/(2)`, Before the slab is removed
`C_(1) = C and C_(2) = kC, C_("net") = ((k)/(k+1))C`
`(Q_(2))/(Q_(2)) = (k+1)/(2k)`