Energy `'E'` is stored in a parallel plate capacitor `'C_(1)'`. An identical uncharged capacitor `'C_(2)'` is connected to it, kept in contact with it for a while and then disconnected, the enegry stored in `C_(2)` is.

Options

A. E/2
B. E/3
C. E/4
D. zero

Answer

C

Explanation

`U_(2)^(1) = (1)/(2) C_(2)V_("common")^(2)`