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A charge +q is placed at the origin O of...

A charge +q is placed at the origin O of x-y axes as shown in the figure. The work done in taking a charge Q from A to B along the straight line AB is

A

`(qQ)/(4pi in_(0)) ((a-b )/(ab))`

B

`(qQ)/(4pi in_(0))((b-a)/(ab))`

C

`(qQ)/(4pi in_(0))((b)/(a^(2))-(1)/(b))`

D

`(qQ)/(4pi in_(0))((a)/(b^(2))-(1)/(b))`

Text Solution

Verified by Experts

The correct Answer is:
A
`W=q_(Delta)V`
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