A `4muF` capacitor is charged by a 200 V supply. It is then disconnected from the supply . And is connected to another uncharged `2muF` capacitor. How much electrostatic energy of the first capacitor is lost in the form of heat and electromagnetic radiation ?

Options

A. Zero
B. `5.33xx10^(-2)`
C. `4xx10^(-2)`
D. `2.67xx10^(-2)`

Answer

D

Explanation

`DeltaU=(1)/(2) (C_(1)C_(2))/(C_(1)+C_(2))(V_(1)+V_(2))^(2), U=(1)/(2)(C_(1)+C_(2))V^(2)`