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Three concentric spherical shells have radii `a, b` and `c(a lt b lt c)` and have surface charge densities `sigma, -sigam` and `sigma` respectively. If `V_(A), V_(B)` and `V_(C)` denote the potentials of the three shells, then for `c = q + b`, we have

A

`V_(C) = V_(B) ne V_(A)`

B

`V_(C) ne V_(B) ne V_(A)`

C

`V_(C) = V_(B)= V_(A)`

D

`V_(C) = V_(A) ne V_(B)`

Text Solution

Verified by Experts

The correct Answer is:
D

`V _(A) = (1)/(4 pi epsi_(0)) ((q_(A))/(a) + (q_(B))/(b) + (q_(C))/(c))`
`V_(B) = (1)/(4 pi epsi_(0)) ((q_(A))/(b) + (q_(B))/(b) + (q_(C))/(c))`
`V_(C) = (1)/( 4 pi epsi_(0)) ( (q_(A))/(c) + (q_(B))/(c) + (q_(C))/(c))`
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