A series combination of `n_(1)` capacitors, each of value `C_(1)`, is charged by a source of potential difference `4 V`. When another parallel combination of `n_(2)` capacitors, each of value `C_(2)`, is charged by a source of potential difference `V`, it has same (total) energy stored in it, as the first combination has. the value of `C_(2)`, in terms of `C_(1)`, is then

Options

A. `(2 C_(1))/( n_(1) n_(2))`
B. `16 ""(n_(2))/(n_(1)) "" C_(1)`
C. `2""(n_(2))/(n_(1)) ""C_(1)`
D. `(16 C_(1))/(n_(1) n_(2))`

Answer

D

Explanation

`C_(s) = (C_(1))/(n_(1)) , U_(s) = (1)/(2) C_(s) (4 v^(2))`
`C_(P) = n_(2) C_(2) , U_(p) = (1)/(2) C_(p) V^(2)`