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How many number of turns of nichrome wir...

How many number of turns of nichrome wire of specific resistance `10^(-6)Omegam` and diameter 2mm that should be wound on a cylinder of diameter 5 cm to obtain a resistance of `40Omega`?

Text Solution

Verified by Experts

If R is the radius of the cylinder
r is the radius of the wire
N is the number of turns
then `R. =(?l)/A therefore R. = (2R N)/r^(2)`
`40 =(10^(-6)(2 xx 2.5 xx 10^(-2) xx N))/(1 xx 10^(-6)) = therefore N=800`
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