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When a bettery is connected to the resis...

When a bettery is connected to the resistance of `10Omega` the current in the circuit is 0.12 A the same battery gives `0.07A` current with `20Omega` calculate `e.m.f` and internal resistance of the battery.

Text Solution

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We know that E=Ir + IR
`I_(1)r + I_(1)R_(1) = I_(2)r + I_(2)R_(2), r=(I_(2)R_(2) - I_(1)R_(1))/(I_(1)-I_(2))`
`r=(0.07 xx 20 - 0.12 xx 10)/(0.12 - 0.07) = (1.4 -1.2)/0.05 = 0.2/0.05 = 4Omega`
Internal resistance `r= 4Omega`
emf E= Ir + IR
`0.12 xx 4 + 0.12 xx 10 = 0.48 + 1.2, E = 1.68` Volt.
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