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When two resistance are connected in par...

When two resistance are connected in parallel then the equivalent resistance is `(6)/(5)Omega` When one of the resistance is removed then the effective resistance is `2Omega`. The resistance of the wire removed will be

A

3 ohm

B

2 ohm

C

`3/5` ohm

D

`6/5` ohm

Text Solution

Verified by Experts

The correct Answer is:
A

`(R_(1)R_(2))/(R_(1) + R_(2)) = 6/5`, If `R_(2)` is removed `R_(1) = 2 Omega`
`(2R_(1))/(2+ R_(1)) = 6/5 rArr 5R_(1) = 6+ 3R_(2) rArr R_(2) = 3Omega`
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