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In the determination of the internal res...

In the determination of the internal resistance of a cell using a potentiometer, when the cell is shunted by a resistance R and connected in the secondary circuit, the balance length is found to be `L_(1)`. On doubling the shunt resistance, the balance length is found to increase to `L_(2)`. The value of the internal resistance is

A

`(2R(L_(2)-L_(1))/(L_(1)-2L_(2)))`

B

`(2R(L_(2)-L_(1))/(2L_(1)-L_(2)))`

C

`(R(L_(2)-L_(1))/(L_(1)-2L_(2)))`

D

`(R(L_(2)-L_(1))/(2L_(1)-L_(2)))`

Text Solution

Verified by Experts

The correct Answer is:
B
`(E/(R+r)) R = K.I`
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