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An electron of mass 9xx10^(-31)kg moves ...

An electron of mass `9xx10^(-31)kg` moves around a nucleus in a circular orbit of radius `2A^(@)` under the action of centripetal force 3.2N. Then the equivalent electric current is

A

`32/(3pi)`

B

`(3pi)/32`

C

`16/(3pi)`

D

`(3pi)/16`

Text Solution

Verified by Experts

The correct Answer is:
A
`I = q/t = (qv)/(2pir)`
since `F = (mv^(2))/r`
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