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A potentiometer wire has resistance 40Om...

A potentiometer wire has resistance `40Omega` and its length is 10m. It is connected by a resistance of `760Omega` in series if emf of battery is 2V then potential gradient is:-

A

`0.5 xx 10^(-6) V/m`

B

`1 xx 10^(-6) V/m`

C

`1 xx 10^(-2) V/m`

D

`2 xx 10^(-6) V/m`

Text Solution

Verified by Experts

The correct Answer is:
C
`R = 760 + 40 = 800 Omega`
`I = 2/800 = 1/400`
` k = V/L = iR/R = (1/400 xx 400)/10 = 1 xx 10^(-2) v/m`
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