Home
Class 12
PHYSICS
The internal resistance of a 2.1 V cell...

The internal resistance of a 2.1 V cell which gives a current of `0.2A` through a resistance of `10 Omega` is

A

`1.0 Omega`

B

`2 Omega`

C

`4 Omega`

D

none

Text Solution

Verified by Experts

The correct Answer is:
D
`V = E - ir , 2 = 2.1 - (.2)r
0.2r = .1 , r = 0.5ohm`
Promotional Banner

Similar Questions

Explore conceptually related problems

The internal resistance of a 2.1 V cell which gives a current 0.2 A through a resistance of 10 Omega

Internal resistance of a cell of 4 V, which gives 0.2 A current through resistance of 10 Omega :

A cell of emf epsilon and internal resistance r gives a current of 0.5 A with an external resistance of 12 Omega and a current of 0.25 A with an external resistance of 25 Omega . Calculate (a) internal resistance of the cell and (b) emf of the cell.

A battery of 6 V internal resistance 0.5 Omega is joined in parallel with another of 10 V and internal resistnace 1 Omega . The combination sends a current through an external resistance of 12 Omega . Find the current through each battery.

A cell of emf 2V and internal resistance 0.1 Omega supplies a current through a coil of resistance 11.0 Omega . The current is being measured by an ammeter whose resistance is 6 Omega . What reading does it give ? What is the percentage difference from the actual current, when the meter is not used ?

The internal resistance of primary cell is 4Omega it generater a current of 0.2A in which chemical resistance connected is providing the current is

Find the minimum number of k cells required to produce a current of 1.5A through a resistance of 30Omega. Given that the emf of each cell is 1.5V and the internal resistance is 1Omega