An alternating voltage is applied across the R-L combination V = 220 sin 120 t and the current I = 4 sin ( 120 t - `60^(@)` ) develops. The power consumption is

An alternating voltage is applied across the R-L combination V = 220 sin 120 t and the current I = 4 sin ( 120 t - 60^(@) ) developes. The power consumption is

An alternating voltage V = V_(0) sin omegat is applied across a circuit. As a result, a current I = I_(0) sin (omegat – p/2) flows in it. The power consumed per cycle is

In an AC circuit the voltage applied is E = E_(0) sin omega t . The resulting current in the circuit is I = I_(0) sin (omega t - (pi)/(2)) . The power consumption in the circuit is given by

In an AC circuit, the current is given by i=5sin(100t-(pi)/2) and the AC potential is V=200sin(100) volt. Then the power consumption is

In an A.C. circuit, the current flowing in inductance is I = 5 sin (100 t – pi//2) amperes and the potential difference is V = 200 sin (100 t) volts. The power consumption is equal to

In an AC circuit voltage applied is e=220 sin 100 t. if the impedance is 110Omega and phase difference between the current and voltage is 60^(@) the power consumption is equal to

In an a.c. Circuit the voltage applied is E=E_(0) sin (omega)t . The resulting current in the circuit is I=I_(0)sin((omega)t-(pi/2)) . The power consumption in the circuit is given by