An inductor has a resistance `R` inductance `L`. It is connected to an `A.C` source of e.m.f. `E_(V)` and angular frequency `omega` then the current `I_(v)` in the circuit is

An inductor has a resistance R and inductance L .It is connected to an A.C source of e.m.f E_(v) and angular frequency omega , then the current I_(v) in the circuit is

An inductance L having a resistance R is connected to an alternating source of angular frequency omega .The quality factor Q of the inductance is

A coil of infuvysnvr 'L' is connected to an a.c. source of emf E and frequency 'f'. The current in the coil is

Resistor of resistance R and capacitor of capacitance C are connected in series to an AC source of angular frequency omega . Rms current in the circuit is I. When frequency of the source is changed to one - third of initial value keeping the voltage same then current is found to be halved. Find the ratio of reactance of capacitor to that with resistance at the original frequency omega .

A coil has inductance of 0.4 H and resistance of 8 Omega .It is connected to an AC source with peak emf 4V and frequency 30/pi Hz .The average power dissipated in the circuit is

An inductance L and capacitance C and resistance R are connected in series across an AC source of angular frequency omega . If omega^(2)gt (1)/(LC) then