For the circuit shown in the figure the rms value of voltage across `R` and coil are `E_(1)` and `E_(2)` respectively.
The power (thermal) developed across the coil is

In the circuit shown in figure, the final voltage drop across the capacitor C is :

In the circuit shown, tp across the 2R resistor muhe voltage drost be

In the series L-C-R circuit shown in the figure, the rms voltage across the resistor and inductor are 400 V and 700 V respectively. If the applied voltage is E=500sqrt(2)sin(omega t) , then the peak voltage across the capacitor is

A resistor R is connected in series with a coil. The system is subjected to an AC supply of peak voltage V_(0) . If the peak voltages dropped across the resistor R and the coil are V_(1) and V_(2) respectively (a) The powerr dissipated in the coil is (V_(0)^(2) - V_(1)^(2) - V_(2)^(2))/(2R) The power dissipated in the circuit is (V_(0)^(2) + V_(1)^(2) - V_(2)^(2))/(2R)

In the circuit shown in figure resistance of each wire is r. Net resistance across

In an LCR series circuit the rms voltages across R,L and C are foundd to be 10 V, 10 V and 20 V respectively. The rms voltage across the entire combination is

In an LCR series circuit the rms voltages across R L and C are found to be 10V,10V and 20Vrespectively.The rms voltage across the entire combination is

In the given circuit the R.M.S values of voltages across the capacitor C, inductor L and resistor R_(1) are 12V, 10V and 5 V respectively. Then the peak voltage across R_(2) is

In the circuit the rms value of voltage across the capacitor C, inductor L and resister R_(1) are respectively 5sqrt(5V) , 10 V and 5V. Then the peak voltage a cross R_(2) is