If power factor of a R-L series circuit is `(1)/(2)` when applied voltage is `V = 100 sin 100 pi t ` volt and resistance of circuit is `200 Omega` then the inductance of the circuit is

In a series L-C-R circuit, currenrt in the circuit is 11A when the applied voltage is 220 V . voltage across the caspcitor is 200 V . If the value of resistor is 20 Omega , then the voltage across the unknown inductor is

The instantaneous values of current and voltage in an ac circuit are i=100 sin 314 r amp and e=200 sin (314 t+pi//3) V respectively. If the resistance is 1 Omega then the reactance of the circuit will be

If power factor is 1//2 in a series RL, circuit R=100 Omega. AC mains is used then L is

Power factor of an L-R series circuit is 0.6 and that of a C-R series circuit is 0.5. If the element (L. C, and R) of the two circuits are joined in series the power factor of this circuit is found to be 1. The ratio of the resistance in the L-R circuit to the resistance in the C-R circuit is

In an L-C-R series circuit, R = sqrt(5) Omega, = 9 Omega, X_(C ) = 7 Omega . If applied voltage in the circuit is 50 V then impedance of the circuit in ohm will be

The power factor of an L-R series circuit is 0.5 and that of a C-R series circuit is 0.2. If the elements (L, C and R) of the two circuit are joined in series and connected to the same ac source, the power factor of this circuit is found to be 1. The ratio of the resistance in the L-R circuit to the resistance in the C-R circuit is

In an alternating series circuit,current is i=100sin(100t)A and voltage is V=100sin(100t+π/6)v .The average power dissipated in the ac circuit is

The instantaneous values of current and voltage in an AC circuit are i=100sin314t amp and e=200sin(314t+pi//3)V respectively. If the resistance is 1Omega then the reactance of the circuit will be

In an A.C. circuit, E=100 sin (500 t) volt and I=1000 sin(500 t +(pi)/3) mA . The power dissipated in the circuit is