In an A.C. circuit, the current flowing in inductance is `I = 5 sin (100 t – pi//2)` amperes and the potential difference is `V = 200 sin (100 t)` volts. The power consumption is equal to

In an AC circuit, the current is given by i=5sin(100t-(pi)/2) and the AC potential is V=200sin(100) volt. Then the power consumption is

In an A.C. Circuit, the current is given by I=6 sin(200 pi t+(pi)/6)A The initial value of the current is

The equation of current in an ac circuit is I = 4 sin (100pit + pi//6) ampere. The current at the beginning (t = 0) will be –

In an AC circuit, the applied potential difference and the current flowing are given by V=20sin100tvolt,I=5sin(100t-pi/2) amp The power consumption is equal to

In an AC circuit voltage applied is e=220 sin 100 t. if the impedance is 110Omega and phase difference between the current and voltage is 60^(@) the power consumption is equal to

In an a.c. circuit, voltage and current are given by : V = 100 sin (100 t) V and I = 100 sin (100 t (pi)/3) mA respectively. The average power dissipated in one cycle is :

In an AC circuit V and I are given by V = 100 sin 100t V and I = 100 sin (100t + pi//3) mA. The power dissipated in the circuit is

In an AC circuit the voltage applied is E = E_(0) sin omega t . The resulting current in the circuit is I = I_(0) sin (omega t - (pi)/(2)) . The power consumption in the circuit is given by

In an A.C. circuit, V and I are given by V = 100 sin ( 100t) volt. I = 100 sin ( 100 t + pi //4) mA The power dissipated in the circuit is