A wire of reistance R is connected in series with an inductor of reactance `omega` L. Then quality factor of `RL` circuit is

An inductance L having a resistance R is connected to an alternating source of angular frequency omega .The quality factor Q of the inductance is

One 2 ohm resistor is connected in series with an inductor of reactance 1 Omega to a 5 V (rms ) A C source . Find the average power dissipated in the circuit .

An inductor of inductance L and ressistor of resistance R are joined in series and connected by a source of frequency omega . Power dissipated in the circuit is

A series AC circuit has a resistance of 4omega and an inductor of reactance 3omega . The impedance of the circuit is z_1 . Now a capacitor of reactance 6omega is connected in the series of above combination, the impedance becomes z_(2) , Then (z_(1))/(z_(2)) will be-

A coil of inductive reactance 31 Omega has a resistance of 8 omega . It is placed in series with a condenser of capacitive reactance 25 Omega . The combination is connected to an ac source of 110 V . The power factor of the circuit is

A 50 Omega resistor is connected in series with an inductor of 0.2 H and capacitor with capacitive reactance 40 Omega . The combination is further connected to an AC source 180 V , 50 Hz. What will be the phase angle between current and voltage ? Also find the value of rms current in circuit.

A coil of inductive reactance 31 Omega has a resistance of 8 Omega . It is placed in series with a condenser of capacitative reactance 25 Omega . The combination is connected to an a.c. source of 110 volt. The power factor of the circuit is

An inductance of 1 mH a condenser of 10 mu F and a resistance of 50 Omega are connected in series. The reactances of inductor and condensers are same. The reactance of either of them will be

A 100 V, AC source of frequency 500 Hz is connected to an LCR circuit with L = 8.1 mH , C = 12.5 mu F, R = 10 Omega all connected in series as shown in the figure. What is the quality factor of the circuit?