If potential difference between the plates of capacitor changes with rate of `(dV)/(dt) = 10^(6)("volt")/("sec)`, and capacitance 1 `mu` F, then find displacement current between tha plates.

Options

A. 1.0A
B. 0.1A
C. 2A
D. 0.2A

Answer

To find the displacement current between the plates of a capacitor, we can use the formula for displacement current \( I_D \):

\[ I_D = C \frac{dV}{dt} \]

Where:
- \( I_D \) is the displacement current,
- \( C \) is the capacitance,
- \( \frac{dV}{dt} \) is the rate of change of the potential difference.

### Step 1: Identify the given values
From the question, we have:
- Capacitance \( C = 1 \, \mu F = 1 \times 10^{-6} \, F \)
- Rate of change of potential difference \( \frac{dV}{dt} = 10^6 \, V/s \)

### Step 2: Substitute the values into the formula
Now we can substitute the values into the formula for displacement current:

\[ I_D = (1 \times 10^{-6} \, F) \times (10^6 \, V/s) \]

### Step 3: Calculate the displacement current
Now we perform the multiplication:

\[ I_D = 1 \times 10^{-6} \times 10^6 = 1 \, A \]

### Conclusion
Thus, the displacement current between the plates of the capacitor is:

\[ I_D = 1 \, A \]