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An electromagnetic wave going through va...

An electromagnetic wave going through vacuum is described by
` E= E_0 sin(kx- omega t), B=B_0sin(kx-omega t)`.
Then

A

`E_(0) =B_(0)`

B

`E_(0) omega = B_(0)`k

C

`E_(0) B_(0) = omega k `

D

`E_(0) k = B_(0) omega`

Text Solution

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The correct Answer is:
D
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