The electrical field in the gap of a condenser charges as `10^(12)Vm^(-1)s^(-1)`. If the radius of each plate of the condenser is `3cm`, the magnetic field at the edge of plate in the gap is

Options

A. 1.67 mT
B. 0.167 `mu`T
C. 0.5 `mu`T
D. 5 `mu` T

Answer

B

Explanation

`int bar(B).bar(dl) = mu_(0) epsilon_(0) (d phi_(E ))/(dt) , " " B(2pi r) = (1)/(C^(2)) (dE)/(dt) pi r^(2)`