A plane electromagnetic wave of wave intensity `6 W//m^(2)` strikes a small mirror of area `40cm(2)`, held perpendicular to the approaching wave. The momentum transferred by the wave to the mirror each second will be

Options

A. `6.4 xx 10^(-7)` kg-m/s
B. `4.8 xx 10^(-8)` kg-m/s
C. `3.2 xx 10^(-9)` kg-m/s
D. `6 xx 10^(-10)`-m/s

Answer

D

Explanation

`P = (2U)/(C) = (2 xx IAt)/( C)`
`(2 xx 6 xx 40 xx 10^(-4) xx 1)/(3 xx 10^(8)) = 1.6 xx 10^(-10)`