A point source of electromagnetic radiation has an average power output of `800W`. The maximum value of electric field at a distance `3.5m` from the source will be `62.6 V/m`, the energy density at a distance `3.5 m` from the source will be- (in `"joule"//m^(3)`)

Options

A. `1.73 xx 10^(-5)`
B. `1.73 xx 10^(-6)`
C. `1.73 xx 10^(-7)`
D. `1.73 xx 10^(-8)`

Answer

D

Explanation

Energy density U = `(1)/(2) epsilon_(0) E_(m)^(2)`