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An AC source having a frequency of 50Hz ...

An `AC` source having a frequency of `50Hz` and voltage supply of `300v` is applied directly to the condenser of capacity `100muF`. The peak and `rms` values of displacement current are

A

`9.42 A, (9.42)/(sqrt(2))` A

B

`(9.42)/(sqrt(2)) A, 9.42 sqrt(2)A `

C

`9.42 sqrt(2) A, 9.42 A`

D

`9.42 A, 9.42 A `

Text Solution

Verified by Experts

The correct Answer is:
C
`I_("rms")=(E_("rms"))/(X_(C)) , I_("rms")=(I_(0))/(sqrt(2))`
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