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Light of frequency n, wave length x trav...

Light of frequency n, wave length x travelling with a velocity v enters into a glass slab of R.I n then frequency, wave length and velocity of the wave in glass slab respectively are

A

`n/mu,lambda,v/u`

B

`n,lambda/mu,v/mu`

C

`n,lambda,v/mu`

D

`n/mu,lambda/mu,v`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze how the frequency, wavelength, and velocity of light change when it enters a glass slab with a given refractive index. Here’s a step-by-step solution: ### Step 1: Understand the given parameters We are given: - Frequency of light in vacuum: \( n \) - Wavelength of light in vacuum: \( \lambda \) - Velocity of light in vacuum: \( v \) - Refractive index of the glass slab: \( \mu \) ### Step 2: Determine the velocity of light in the glass slab The refractive index \( \mu \) is defined as the ratio of the speed of light in vacuum \( c \) to the speed of light in the medium \( v_m \): \[ \mu = \frac{c}{v_m} \] Since we are considering the speed of light in vacuum as \( v \), we can express the speed of light in the glass slab as: \[ v_m = \frac{v}{\mu} \] ### Step 3: Analyze the frequency of light in the glass slab The frequency of light does not change when it enters a different medium. Therefore, the frequency of light in the glass slab remains the same: \[ \text{Frequency in glass} = n \] ### Step 4: Determine the wavelength of light in the glass slab The relationship between the speed of light, frequency, and wavelength is given by: \[ v = f \cdot \lambda \] In the glass slab, the speed of light is \( v_m \) and the wavelength is \( \lambda_m \). Therefore, we can write: \[ v_m = n \cdot \lambda_m \] Substituting \( v_m \) from Step 2 into this equation: \[ \frac{v}{\mu} = n \cdot \lambda_m \] From this, we can solve for the wavelength in the glass slab: \[ \lambda_m = \frac{v}{\mu \cdot n} \] ### Step 5: Summarize the results Now we have: - Frequency in glass: \( n \) - Wavelength in glass: \( \frac{\lambda}{\mu} \) (since \( \lambda = \frac{v}{n} \)) - Velocity in glass: \( \frac{v}{\mu} \) ### Final Answer Thus, the frequency, wavelength, and velocity of the wave in the glass slab are: - Frequency: \( n \) - Wavelength: \( \frac{\lambda}{\mu} \) - Velocity: \( \frac{v}{\mu} \)
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Knowledge Check

  • Electromagnetic radiation of frequency n , wavelength lambda , travelling with velocity v in air, enters a glass slab of refractive index mu . The frequency, wavelength and velocity of light in the glass slab will be respectively

    A
    `n/mu, lambda/mu, v/mu`
    B
    `n, lambda/mu, v/mu`
    C
    `n, lambda, v/mu`
    D
    `n/mu, lambda/mu, v`
  • An electromagnetic radiation of frequency v, wavelength lamda , travelling with velocity c in air, enters a glass slab of refractive index mu . The frequency, wavelength and velocity of light in the glass slab will be respectively.

    A
    `(v)/(mu),(lamda)/(mu)` and `(c)/(mu)`
    B
    `v,(lamda)/(mu)` and `(c)/(mu)`
    C
    `v,2lamda` and `(c)/(mu)`
    D
    `(2v)/(mu),(lamda)/(mu)` and c
  • An electromagnetic radiation of frequency n, wavelength lambda , travelling with velocity v in air, entres a glass slab of refractive index mu . The frequency, wavelength and velocity of light in the glass slab will be respectively

    A
    `n, 2 lambda` and `(v)/(mu)`
    B
    `(2n)/(mu), (lambda)/(mu)` and v
    C
    `(n)/(mu), (lambda)/(mu)` and `(v)/(mu)`
    D
    `n, (lambda)/(mu)` and `(v)/(mu)`
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