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A person can see clearly objects between...

A person can see clearly objects between 15 and 100 cm from his eye. The range of his vision if he wears close fitting spetancles having a power of -0.8 diopter is

A

5 to 500 cm

B

12 to 250 cm

C

17 to 500 cm

D

17 to 250 cm

Text Solution

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The correct Answer is:
To solve the problem, we need to determine the new range of vision for a person who can normally see objects clearly between 15 cm and 100 cm from his eye when he wears spectacles with a power of -0.8 diopters. ### Step-by-Step Solution: 1. **Understanding the Power of the Lens:** The power (P) of a lens is given by the formula: \[ P = \frac{1}{f} \] where \( f \) is the focal length in meters. Given that the power of the spectacles is -0.8 diopters, we can find the focal length: \[ f = \frac{1}{P} = \frac{1}{-0.8} = -1.25 \text{ meters} = -125 \text{ cm} \] 2. **Finding the New Near Point:** The near point of the eye without spectacles is 15 cm. When wearing spectacles, the effective near point (D) can be calculated using the lens formula: \[ \frac{1}{v} = \frac{1}{f} + \frac{1}{u} \] Here, \( u \) is the object distance (the near point), and \( v \) is the image distance (the new near point with spectacles). We can rearrange the formula to find \( v \): \[ \frac{1}{v} = \frac{1}{-125} + \frac{1}{-15} \] Calculating the right-hand side: \[ \frac{1}{v} = -0.008 + -0.0667 = -0.0747 \] Therefore, \[ v = \frac{1}{-0.0747} \approx -13.39 \text{ cm} \] Since we are interested in the absolute value, the new near point is approximately 13.39 cm. 3. **Finding the New Far Point:** The far point of the eye without spectacles is 100 cm. We will use the same lens formula to find the new far point: \[ \frac{1}{v} = \frac{1}{f} + \frac{1}{u} \] Here, \( u \) is the object distance (the far point), and we want to find \( v \) (the new far point with spectacles): \[ \frac{1}{v} = \frac{1}{-125} + \frac{1}{-100} \] Calculating: \[ \frac{1}{v} = -0.008 + -0.01 = -0.018 \] Therefore, \[ v = \frac{1}{-0.018} \approx -55.56 \text{ cm} \] Again, taking the absolute value, the new far point is approximately 55.56 cm. 4. **Final Range of Vision:** The new range of vision for the person wearing the spectacles is from approximately 13.39 cm to 55.56 cm. ### Conclusion: The range of vision for the person wearing spectacles with a power of -0.8 diopters is approximately **13.39 cm to 55.56 cm**.

To solve the problem, we need to determine the new range of vision for a person who can normally see objects clearly between 15 cm and 100 cm from his eye when he wears spectacles with a power of -0.8 diopters. ### Step-by-Step Solution: 1. **Understanding the Power of the Lens:** The power (P) of a lens is given by the formula: \[ P = \frac{1}{f} ...
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