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A spherical surface of radius of curvatu...

A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O, and `PO=OQ`. The distance `PO`

A

5R

B

3R

C

2R

D

1.5R

Text Solution

Verified by Experts

The correct Answer is:
A
`mu_(2)/v-mu_(1)/u=(mu_(2)-mu_(1))/R,1.5/(PO) + 1/(PO)=(1.5-1)/R`
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Knowledge Check

  • A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The center of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The ling PQ cuts the surface at a point O, and PO=OQ . The distance PO is equal to

    A
    5R
    B
    3R
    C
    2R
    D
    1.5R

  • In the figure, an air lens is cut a cylinder of glass of refractive index 1.5 . The nature of the lens is

    A
    diveriging
    B
    converging
    C
    neither diverging nor converging
    D
    none of these

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    A
    `R/2`
    B
    R
    C
    2R
    D
    1.5R

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