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An infinitely long rod lies along the ax...

An infinitely long rod lies along the axis of a concave mirror of focal length f. The near end of the rod is distance `u gt f` from the mirror. Its image will have length

A

`(uf)/(u-f)`

B

`(uf)/(u+f)`

C

`f^(2)/(u+f)`

D

`f^(2)/(u-f)`

Text Solution

Verified by Experts

The correct Answer is:
D
`1/f=1/v_(2) + 1/u,1/f=1/v_(1)+1/oo` Length of mage= `v_(2)-v_(2)`
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