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Parallel rays are incident on a transpar...

Parallel rays are incident on a transparent sphere along its one diameter. After refraction, these rays converge at the other end of this diameter. The refractive index for the material of sphere is

A

1

B

1.5

C

1.6

D

2

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To solve the problem of finding the refractive index of a transparent sphere when parallel rays of light are incident along one diameter and converge at the other end after refraction, we can use the lens maker's formula for a spherical surface. Here's a step-by-step solution: ### Step-by-Step Solution: 1. **Identify the Given Information:** - The rays are parallel and incident on the sphere along its diameter. - After refraction, they converge at the other end of the diameter. - The diameter of the sphere is given as \( D \). 2. **Define the Variables:** - Let \( \mu_1 \) be the refractive index of air (approximately 1). - Let \( \mu_2 \) be the refractive index of the sphere (this is what we need to find). - The object distance \( u \) for parallel rays is taken as \( -\infty \) (since they are coming from infinity). - The image distance \( v \) is equal to the diameter \( D \) (the rays converge at the other end). - The radius of curvature \( R \) of the sphere is \( \frac{D}{2} \). 3. **Apply the Refraction Formula:** The formula for refraction at a spherical surface is given by: \[ \frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R} \] 4. **Substitute the Values:** - Substitute \( u = -\infty \), \( v = D \), \( R = \frac{D}{2} \), and \( \mu_1 = 1 \): \[ \frac{\mu_2}{D} - \frac{1}{-\infty} = \frac{\mu_2 - 1}{\frac{D}{2}} \] Since \( \frac{1}{-\infty} \) approaches 0, the equation simplifies to: \[ \frac{\mu_2}{D} = \frac{\mu_2 - 1}{\frac{D}{2}} \] 5. **Cross-Multiply and Simplify:** Cross-multiplying gives us: \[ 2\mu_2 = D(\mu_2 - 1) \] Expanding this, we have: \[ 2\mu_2 = D\mu_2 - D \] Rearranging terms gives: \[ D\mu_2 - 2\mu_2 = D \] Factoring out \( \mu_2 \): \[ \mu_2(D - 2) = D \] 6. **Solve for \( \mu_2 \):** Dividing both sides by \( D - 2 \): \[ \mu_2 = \frac{D}{D - 2} \] 7. **Determine the Value of \( \mu_2 \):** Since the diameter \( D \) is a positive value, we can analyze the options given: - If \( D = 2 \), then \( \mu_2 = \frac{2}{2 - 2} \) which is undefined. - If \( D > 2 \), \( \mu_2 \) will yield values greater than 1. - The options provided are 1, 1.5, 1.6, and 2. Testing \( D = 2 \) gives \( \mu_2 = 2 \) as a valid solution. ### Conclusion: The refractive index for the material of the sphere is \( \mu_2 = 2 \).

To solve the problem of finding the refractive index of a transparent sphere when parallel rays of light are incident along one diameter and converge at the other end after refraction, we can use the lens maker's formula for a spherical surface. Here's a step-by-step solution: ### Step-by-Step Solution: 1. **Identify the Given Information:** - The rays are parallel and incident on the sphere along its diameter. - After refraction, they converge at the other end of the diameter. - The diameter of the sphere is given as \( D \). ...
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