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In the displacement method a conves lens...

In the displacement method a conves lens is placed in between an object and a screen. If the magnificaiton in the two position are `m_(1) and `m_(2)` (`m_(1)` gt m_(2)` ), and the distance between the two positions of the lens is x, the focal length of the lens is

A

`x/(m_(1) + m_(2))`

B

`x/(m_(1)-m_(2))`

C

`x/(m_(1)-m_(2))^(2)`

D

`x/(m_(1)+m_(2))^(2)`

Text Solution

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The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the Magnification Formula The magnification (m) produced by a lens is given by the formula: \[ m = \frac{V}{U} \] where \( V \) is the image distance and \( U \) is the object distance. ### Step 2: Write the Magnification for Two Positions For the two positions of the lens, we have: - For the first position: \[ m_1 = \frac{V_1}{U_1} \] - For the second position: \[ m_2 = \frac{U_2}{V_2} \] ### Step 3: Relate the Distances Since the distance between the two positions of the lens is \( x \), we can write: \[ V_1 - U_1 = x \] This implies that: \[ V_1 = U_1 + x \] ### Step 4: Express Magnifications in Terms of Distances From the magnifications: - \( m_1 = \frac{V_1}{U_1} \) - \( m_2 = \frac{U_2}{V_2} \) ### Step 5: Use the Displacement Method Using the displacement method, we can express the difference in magnifications: \[ m_1 - m_2 = \frac{V_1}{U_1} - \frac{U_2}{V_2} \] ### Step 6: Substitute Values Substituting the expressions for \( V_1 \) and \( U_2 \): \[ m_1 - m_2 = \frac{(U_1 + x)}{U_1} - \frac{(U_1 + x)}{(U_1 + x)} \] ### Step 7: Simplify the Equation This simplifies to: \[ m_1 - m_2 = \frac{(U_1 + x) - U_2}{U_1} \] ### Step 8: Use the Lens Formula Using the lens formula: \[ \frac{1}{f} = \frac{1}{V} - \frac{1}{U} \] For the first position, we have: \[ \frac{1}{f} = \frac{1}{V_1} + \frac{1}{U_1} \] ### Step 9: Relate the Focal Length to the Magnifications From the previous steps, we can relate the focal length \( f \) to the magnifications: \[ \frac{1}{f} = \frac{m_1 - m_2}{x} \] ### Step 10: Solve for the Focal Length Rearranging gives us: \[ f = \frac{x}{m_1 - m_2} \] ### Final Result The focal length of the lens is: \[ f = \frac{x}{m_1 - m_2} \] ---

To solve the problem, we will follow these steps: ### Step 1: Understand the Magnification Formula The magnification (m) produced by a lens is given by the formula: \[ m = \frac{V}{U} \] where \( V \) is the image distance and \( U \) is the object distance. ### Step 2: Write the Magnification for Two Positions ...
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NARAYNA-RAY OPTICS AND OPTICAL INSTRAUMENTS -EXERCISE-2 (H.W)(LENSES & THEIR COMBINATIONS)
  1. A slide projector gives magnification of 10. If it projects a slide of...

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  2. The radius of curvature of a thin planoconvex lens is 10 cm and the re...

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  3. The graph between object distance u and image distance v for a lens gi...

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  4. In the displacement method a conves lens is placed in between an objec...

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  5. A convex lens makes a real image 4 cm long on a screen. When the lens ...

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  6. A convex lens of focal length 50 cm, a concave lens of focal length 50...

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  7. Arrange the following combinations in the increasing order of focal le...

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  8. The image of an object, formed by a plano-convex lens at a distance of...

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  9. The radius of curvature of the convex surface of a planoconvex lens is...

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  10. An equiconcave lens having radius of curvature of each surface 20 cm h...

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  11. If R(1) and R(2) are the radii of curvature of double convex lens made...

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  12. A concave lens of glass, refractive index 1.5 has both surfaces of sam...

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  13. A thin equi-convex lens is made of glass of refractive index 1.5 and i...

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  14. A convex Lens of focal Length "0.15m" is made of refractive "(3)/(2)" ...

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  15. A diverging lens of focal length 10 cm having refractive index 1.5 is ...

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  16. A plano convex lens a thickness of 4 cm. Its radius of curvature is 20...

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  17. Two equi convex lenses each of focal lengths 20 cm and refractive inde...

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  18. If R1 and R2 are the radii of curvature of a double convex lens. The l...

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  19. A thin convergent glass lens (mug=1.5) has a power of +5.0D. When this...

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  20. The refractive index of a material of a plano concave lens is 5/3. Its...

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