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The maximum value of index of refraction...

The maximum value of index of refraction of a material of a prism which allows the passage of light through it when the refracting angle of prism is A is

A

`sqrt(1 + sin^(2)(A/2))`

B

`sqrt(1 + cos^(2)(A/2))`

C

`sqrt(1+ tan^(2)(A/2))`

D

`sqrt(1 + cot^(2)(A/2))`

Text Solution

Verified by Experts

The correct Answer is:
D
`A=2C,mu=1/(sinC)`
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